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If vecaxx(vecbxxvecc)=(vecaxxvecb)xxvecc...

If `vecaxx(vecbxxvecc)=(vecaxxvecb)xxvecc` for non coplanar `veca,vecb,vecc` then……

A

`(veccxxveca)xx vecb =vec0`

B

`vecc xx (vecaxxvecb)=vec0`

C

`vecbxx (vecc xxveca)=vec0`

D

`veccxxvecaxxvecb=vecb xx (veccxxveca) = vec0`

Text Solution

Verified by Experts

The correct Answer is:
a,c,d
` veca xx (vecbxxvecc)=(vecaxxvecb)xxvecc`
`or (veca.vecc)vecb- (veca. Vecb) vecc = (veca.vecc) vecb- (vecc.vecv)veca `
`or (veca -vecb) vecc - (vecc.vecb)veca=0`
`or (vecc xx veca) xx vecb =0`
`or vecb xx (vecc xx veca) = (vecc xx veca) xx vecb =vec0`
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