Home
Class 11
MATHS
A(1),A(2), …. A(n) are the vertices of a...

`A_(1),A_(2), …. A_(n)` are the vertices of a regular plane polygon with n sides and O ars its centre. Show that `sum_(i=1)^(n-1) (vec(OA_(i))xxvec(OA)_(i+1))=(1-n) (vec(OA)_2 xx vec(OA)_(1))`

Text Solution

Verified by Experts

`vec(OA)_(1) , vec(OA)_(1) …..,vec(OA)_(n)` All vectors are of same magnitude, say a, and angle between any two consecuitve vectors parallel to the plane of the plane of the polygon.
Let ` vec(OA)_(1) xx vec(OA)_(2)=a^(2) sin "" (2pi)/n hatp`
Now `underset(i=1)overset(n-1)sumvec(OA)_(1)xx vec(OA)_(i+1)= underset(i+1)overset(n-1)suma^(1)sin""(2pi)/n hatp`
` (n-1) a^(2) sin "" (2pi)/n hatp`
` (n-1) [-vec(OA)_(2) xx vec(OA)_(1)]`
`(1-n) [ vec(OA)_(2) xx vec(OA)_(1)]`
R.H.S
Promotional Banner

Topper's Solved these Questions

  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE|Exercise Exercise 2.1|18 Videos
  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE|Exercise Exercise 2.2|15 Videos
  • CONIC SECTIONS

    CENGAGE|Exercise Solved Examples And Exercises|1255 Videos
  • LIMITS AND DERIVATIVES

    CENGAGE|Exercise Solved Examples And Exercises|288 Videos

Similar Questions

Explore conceptually related problems

A_1,A_2,..., A_n are the vertices of a regular plane polygon with n sides and O as its centre. Show that sum_(i=1)^n vec (OA)_i xx vec(OA)_(i+1)=(1-n)(vec (OA)_2 xx vec(OA)_1)

If A_(1), A_(2),..,A_(n) are any n events, then

Let A_1,A_2,....A_n be the vertices of an n-sided regular polygon such that , 1/(A_1A_2)=1/(A_1A_3)+1/(A_1A_4) . Find the value of n.

The value of sum_(i=1)^(13) (n^(n) + i^(n-1)) is

If a_(1), a_(2) …… a_(n) = n a_(n - 1) , for all positive integer n gt= 2 , then a_(5) is equal to

If a_(1), a_(2), a_(3), …..a_(n) is an arithmetic progression with common difference d. Prove that tan[tan^(-1)((d)/(1+a_(1)a_(2)))+tan^(-1)((d)/(1+a_(2)a_(3)))+…+tan^(-1)((d)/(1+a_(n)a_(n-1)))]=(a_(n)-a_(1))/(1+a_(1)a_(n))

If are the n Arithmetic means between a and b , then 2sum_(I - 1)^(n)a_(i) =

If a_(1), a_(2) , ……. A_(n) are in H.P., then the expression a_(1)a_(2) + a_(2)a_(3) + ….. + a_(n - 1)a_(n) is equal to