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The product of n positive numbers is uni...

The product of n positive numbers is unity, then their sum is

Text Solution

Verified by Experts

The correct Answer is:
`(x^(2))/(3)+3x-log|x-1|+8log|x-2|+C`
Here, the degree of numerator is greater than that of denominator.
So, we divide the numerator by denominator to obtain
`int(x^(3))/((x-1)(x-2))dx=int(x+3 +(7x-6)/((x-1)(x-2)))dx`
`=(x^(2))/(3)+3x+int((-1)/((x-1))+(8)/((x-2)))dx`
`=(x^(2))/(3)+3x-log|x-1|+8log|x-2|+C`
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