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Let a, b gt 0 satisfies a^(3)+b^(3)=a-b....

Let `a`, `b gt 0` satisfies `a^(3)+b^(3)=a-b`. Then

A

`a^(2)+b^(2)=1`

B

`a^(2)+ab+b^(2) lt 1`

C

`a^(2)+b^(2) gt 1`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`(b)` `a^(2)+ab+b^(2)=(a^(3)-b^(3))/(a-b)=(a^(3)-b^(3))/(a^(3)+b^(3)) lt 1`.
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