If the first, fifth and last terms of an `A.P.` is `l`, `m`, `p`, respectively, and sum of the `A.P.` is `((l+p)(4p+m-5l))/(k(m-l))` then `k` is
A
`2`
B
`3`
C
`4`
D
`5`
Text Solution
Verified by Experts
The correct Answer is:
A
`(a)` Let common difference `=d` and number of terms `=n` `:.T_(s)=m=l+4dimpliesd=(m-l)//4` `:.T_(n)=p=l+((n-1)(m-1))/(4)` `implies n=((4P+m-5)/(m-1))` `:.` Sum of `n` terms of `A.P.=(n)/(2)["First term"+"Last term"]` `=[(4p+m-5l)/(m-l)]*(1)/(2)[l+p]`........`(i)` Comparing equation `(i)` with the given summation, we get `k=2`.