If `a_(1),a_(2),a_(3),…` are in `G.P.`, where `a_(i) in C` (where `C` satands for set of complex numbers) having `r` as common ratio such that `sum_(k=1)^(n)a_(2k-1)sum_(k=1)^(n)a_(2k+3) ne 0` , then the number of possible values of `r` is
A
`2`
B
`3`
C
`4`
D
`5`
Text Solution
Verified by Experts
The correct Answer is:
C
`(c )` We have `a_(1)+a_(3)+a_(5)+….+a_(2n-1)` `=a_(5)+a_(7)+a_(9)+…+a_(2n-3)` `=r^(4)(a_(1)+a_(3)+…+a_(2n-1))` `impliesr^(4)=1` `impliesr=1,-1,i` and `-i`.