The first three terms of a geometric sequence are `x`, `y`,`z` and these have the sum equal to `42`. If the middle term `y` is multiplied by `5//4`, the numbers `x`, `(5y)/(4)`, `z` now form an arithmetic sequence. The largest possible value of `x` is
A
`6`
B
`12`
C
`24`
D
`20`
Text Solution
Verified by Experts
The correct Answer is:
C
`(c )` The three terms of the geometric sequence with the common ratio `r` are `x`, `xr`, `xr^(2)`. ,brgt `:.x+xr+xr^(2)=42` After multiplying the middle term by `5//4`, we will get an arithmetic sequence. ,brgt `:.(5)/(4)xr-x=xr^(2)-(5)/(4)xr` `:.2r^(2)-5r+2=0 :. r=(1)/(2)` and `r=2` On substituting these in `x+xr+xr^(2)=42`, we get `x=6` or `24`
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CENGAGE-PROGRESSION AND SERIES-ARCHIVES (MATRIX MATCH TYPE )
