The sequence `{x_(k)}` is defined by `x_(k+1)=x_(k)^(2)+x_(k)` and `x_(1)=(1)/(2)`. Then `[(1)/(x_(1)+1)+(1)/(x_(2)+1)+...+(1)/(x_(100)+1)]` (where `[.]` denotes the greatest integer function) is equal to
If int(m^((1)/(x)))/(x^(2))dx=k(m^((1)/(x)))+c then k is:
If (kx)/((x + 2) (x - 1)) = (2)/(x + 2) + (1)/(x -1) , then the value of k is
If the staight line (x-1)/k=(y-2)/2=(z-3)/3 and (x-2)/3=(y-3)/k =(z-1)/3 intersect at a point , then the integer k is equal to
if int (3^((1)/(x)))/(x^(2)) dx = k (3^((1)/(x))) + c , then the value of k is
Evaluate lim_(x to 1) sum_(k=1)^(100) x^(k) - 100)/(x-1).
Consider any set of observations x_(1),x_(2),x_(3),..,x_(101) . It is given that x_(1) lt x_(2) lt x_(3) lt .. Lt x_(100) lt x_(101) , then the mean deviation of this set of observations about a point k is minimum when k equals
If the lines (x-1)/(-3)=(y-2)/(2k) =(z-3)/2 and (x-1)/(3k) =(y-5)/1=(z-6)/(-5) are mutually perpendicular then k is equal to
Given (1-x^(3))^(n)=sum_(k=0)^(n)a_(k)x^(k)(1-x)^(3n-2k) then the value of 3*a_(k-1)+a_(k) is
CENGAGE-PROGRESSION AND SERIES-ARCHIVES (MATRIX MATCH TYPE )
