There is a certain sequence of positive real numbers. Beginning from the third term, each term of the sequence is the sum of all the previous terms. The seventh term is equal to `1000` and the first term is equal to `1`. The second term of this sequence is equal to
A
`246`
B
`(123)/(2)`
C
`(123)/(4)`
D
`124`
Text Solution
Verified by Experts
The correct Answer is:
B
`(b)` Sequence is `t_(1)+t_(2)+t_(3)+t_(4)+…` `t_(3)=t_(1)+t_(2)`, `t_(7)=1000` `t_(1)=1` but `t_(7)=t_(1)+t_(2)+t_(3)+t_(4)+t_(5)+t_(6)` `1000=2(t_(1)+t_(2)+t_(3)+t_(4)+t_(5))` `=4(t_(1)+t_(2)+t_(3)+t_(4))` `=8(t_(1)+t_(2)+t_(3))` `=16(t_(1)+t_(2))` `:.t_(1)+t_(2)=125//2` `:. t_(2)=125//2-1=123//2`