The sequence `{x_(1),x_(2),…x_(50)}` has the property that for each `k`, `x_(k)` is `k` less than the sum of other `49` numbers. The value of `96x_(20)` is
A
`300`
B
`315`
C
`1024`
D
`0`
Text Solution
Verified by Experts
The correct Answer is:
B
`(b)` We have `x_(k)+k=S-x_(k)` where `x_(1)+x_(2)+…+x_(k)=S` `implies2x_(k)+k=S` `:.2sum_(k=1)^(50)x_(k)+sum_(k=1)^(50)k=sum_(k=1)^(50)S` ,brgt `implies2(S)+(50.51)/(2)=50S` `implies48(S)=25.51` `impliesx_(20)=((25.51)/(48)-20)(1)/(2)=(315)/(96)`