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If two events `A` and `B` such that `P(A')=0.3`, `P(B)=0.5` and `P(AnnB)=0.3`, then `P(B//AuuB')` is

A

`3//8`

B

`2//3`

C

`5//6`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
A
`(a)` `P(B//AuuB')=(P(Bnn(AuuB')))/(P(AuuB'))`
`=(P(AnnB))/(P(A)+P(B')-P(AnnB'))`
`=(0.3)/(0.7+0.5-0.4)=(3)/(8)`
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