Find the area of the closed figure bounded by the curves `y=sqrt(x),y=sqrt(4-3x)a n dy=0`

Explanation

`A=overset(1)underset(0)int(sqrt(xdx))+overset(4//3)underset(1)intsqrt(4-3xdx)`
`=((x^(3//2))/(3//2))_(0)^(1)+(((4-3x)^(3//2))/(-3(3//2)))_(1)^(4//3)`
`=(2)/(3)+(2)/(3)[(1)/(3)]`
`=(2)/(3)+(2)/(9)=(8)/(9)" sq. units"`