Home
Class 12
MATHS
The area bounded by the curves y=cosx an...

The area bounded by the curves `y=cosx` and `y=sinx` between the ordinates `x=0` and `x=(3pi)/2` is

A

`4sqrt(2)+1`

B

`4sqrt(2)-1`

C

`4sqrt(2)+2`

D

`4sqrt(2)-2`

Text Solution

Verified by Experts

The correct Answer is:
D

`overset(pi//4)underset(0)int(cos x - sin x ) dx+overset(5pi//4)underset(pi//4)int(sin x - cos x ) dx+overset(3pi//2)underset(5pi//2)int( cos x - sin x) =4sqrt(2)-2`
Promotional Banner

Topper's Solved these Questions

  • AREA

    CENGAGE|Exercise JEE Advanced Previous Year|9 Videos
  • AREA

    CENGAGE|Exercise Single Correct Answer Type|27 Videos
  • AREA

    CENGAGE|Exercise Exercise (Numerical)|16 Videos
  • APPLICATIONS OF DERIVATIVES

    CENGAGE|Exercise Subjective Type|2 Videos
  • AREA UNDER CURVES

    CENGAGE|Exercise Question Bank|10 Videos

Similar Questions

Explore conceptually related problems

The area bounded by the curve y=3/|x| and y+|2-x|=2 is

The area bounded by the curve y = sin x between the ordinates x = 0, x = pi and the x-axis is

Find the area bounded by the curve y=(x-1)(x-2)(x-3) lying between the ordinates x=0a n dx=3.

Find the area of the region bounded by the curves y=sqrt(x+2) and y=(1)/(x+1) between the lines x=0 and x=2.

Find the area bounded by the curves y = sin x, y = cos x between x axis, x = 0 and x = (pi)/(2)

Find the area bounded by the curves x+2|y|=1 and x=0 .

Sketch the curve y = x^(3) find the area bounded by the above curve, the a-axis between the ordinates x = 02 and x = 1

Find the area bounded by the curve f(x)=x+ sin x and its inverse function between the ordinates x=0" to "x=2pi .