Home
Class 12
MATHS
If origin is shifted to (-2,3) then tran...

If origin is shifted to `(-2,3)` then transformed equation of curve `x^2 +2y-3=0` w.r.t. to `(0,0)` is

A

`x^(2)-4x +2y +4 = 0`

B

`x^(2) - 4x - 2y - 5 = 0`

C

`x^(2) +4x +2y - 5 = 0`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Transformed equation
`(x+2)^(2) +2(y-3) -3 = 0`
`rArr x^(2) +4x +2y - 5 = 0`
Promotional Banner

Topper's Solved these Questions

  • COORDINATE SYSTEM

    CENGAGE|Exercise Comprehension Type|4 Videos

  • COORDINATE SYSTEM

    CENGAGE|Exercise Multiple Correct Answers Type|2 Videos

  • CONTINUITY AND DIFFERENTIABILITY

    CENGAGE|Exercise Question Bank|1 Videos

  • COORDINATE SYSYEM

    CENGAGE|Exercise JEE Main Previous Year|6 Videos

Similar Questions

Explore conceptually related problems

Find the asymptotes of the curve x y-3y-2x=0 .

From the curve y=x, draw 2x+y+3=0.

If the origin is shifted to the point (1,-2) without the rotation of the axes, what do the following equations become? (i) 2x^2+y^2-4x+4y=0 (ii) y^2-4x+4y+8=0

Find the equation of tangent and normal to the curve y = x^(2) + 3x + 2 at (0, 2)

Find the equation to which the equation x^2+7x y-2y^2+17 x-26 y-60=0 is transformed if the origin is shifted to the point (2,-3), the axes remaining parallel to the original axies.

Find the equations of the tangents drawn to the curve y^2-2x^3-4y+8=0.

Equation of the normal to the curve y=2x^(2)+3sinx at x = 0 is

Transform the equation 3x+4y+12=0 in to normal form.

Find the equation of tangent to the circle x^(2) + y^(2) + 2x -3y -8 = 0 at (2,3)

Shift the origin to a suitable point so that the equation y^2+4y+8x-2=0 will not contain a term in y and the constant term.