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Find the joint equation of the pair of l...

Find the joint equation of the pair of lines which pass through the origin and are perpendicular to the lines represented the equation `y^2+3x y-6x+5y-14=0`

A

`y^(2) - 3xy = 0`

B

`3y^(2) - xy = 0`

C

`x^(2) - 3xy = 0`

D

`3x^(2) - xy = 0`

Text Solution

Verified by Experts

The correct Answer is:
C
Homogeneous part of the given equation is `y^(2) +3xy =0`, which represents straight lines `y =0` and `y+3x =0`. Now lines perpendicular to these lines are `x =0` and `x -3y =0`. So combined equation of above lines is
`x^(2) - 3xy =0`
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