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about to only mathematics

A

9

B

3

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
B
Any point on `x +y =1` is `(t,1-t)`.
Thus, equation of chord with this point as mid point is `y (1-t) -2a (x+t) = (1-t)^(2) - 4at`.
It passes through `(a,2a)`, so `t^(2) -t +2a^(2) -2a +1 =0`. This should have two distinct real roots
`:. a^(2) -a lt 0 rArr 0 lt a lt 1 rArr 0 4a lt 4`
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