Find the derivative of `y = 10^(3x)`

Answer

B

Explanation

Foci of hyperbola are `(+- sqrt(41),0)`
`:. P` lies on the circle `x^(2) + y^(2) = 41`
Any point on hyperbola is `(4 sec theta, 5 tan theta)`
`rArr 16 sec^(2) theta + 25 tan^(2) theta = 41`
`rArr tan theta = (5)/(sqrt(41))` and `sec theta = sqrt((66)/(41))`
`:. PF_(1) + PF_(2) = e (4 sec theta -(a)/(e)) +e (4 sec theta +(a)/(e))`
`= 8 esec theta = 2 sqrt(66)`