Find the derivative of `y = e^(x^2)`.

Answer

B, C

Explanation

Focus of ellipse lying to the right of the y-axis is `S_(1) (ae,0)` Focus of hyperbola lying to the right of the y-axis is `S_(2)(aE//2,0)` Now `P(alpha, beta)` is equidistance from `S_(1)` and `S_(2)`
`:. S_(1)P = S_(2)P rArr a - e alpha = E alpha -((a)/(2))`. (1)
Also P lies on perpendicular bisector of `S_(1)S_(2)`
`:. alpha = (ae+(a)/(2)E)/(2)`
From (1) and (2), `E^(2) + 3eE + (2e^(2)-6) =0`
`rArr E = (sqrt(e^(2)+24)-3e)/(2)`