The length of the tangent from any point on the circle to the circle `(x-3)^2 + (y + 2)^2 =5r^2` to the circle ` (x-3)^2 + (y + 2)^2 = r^2` is 4 units. Then the area between the circles is

Answer

`16 pi`

Explanation

From the figure,
`5r^(2)=16+r^(2)`
`:. R^(2)= 4`
`:. R = 2`
`:. ` Area between circles
`=pi(5r^(2))=pi(r^(2))=4pir^(2)=16pi`
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