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If one of the diameters of the circle x^...

If one of the diameters of the circle `x^2+y^2-2 x-6 y+6` `=0` is a chord to the circle with centre at `(2,1)` then the radius of the circle is equal to.

A

`sqrt(3)`

B

`sqrt(2)`

C

3

D

2

Text Solution

Verified by Experts

The correct Answer is:
3
The given circle is `x^(2)+y^(2)-2x-6y+6=0`
Its center is `H(1,3)` and radius is 2.
`AH=2`
Radius of the required circle `=AC`
`= sqrt(AH^(2)+CH^(2))=sqrt(2^(2)+5)=3`
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