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A circle with center (a , b) passes thro...

A circle with center `(a , b)` passes through the origin. The equation of the tangent to the circle at the origin is (a)`a x-b y=0` (b) `a x+b y=0` (c)`b x-a y=0` (d) `b x+a y=0`

A

`ax-by=0`

B

`ax+by=0`

C

`bx-ay=0`

D

`bx+ay=0`

Text Solution

Verified by Experts

The correct Answer is:
2

Obviously , the slope of the tangent will be `((1)/(b//a)), i.e., -(a)/(b)`.
Hence, the equation of the tangent is `y= -(a)/(b)x, i.e., ` by `+ax =0`
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