The chords of contact of tangents from three points `A ,Ba n dC` to the circle `x^2+y^2=a^2` are concurrent. Then `A ,Ba n dC` will be concyclic (b) be collinear form the vertices of a triangle none of these

Options

A. be concyclic
B. be collinear
C. form the vertices of a triangle
D. none of these

Answer

2

Explanation

Let the coordinates of A,B, and C be `(x_(1),y_(1)),(x_(2),y_(2))` and `(x_(3),y_(3))` , respectively. Then, the chords of contact of tangents drawn from A,B, and C are `x x_(1)+y y_(1)= a^(2), x x_(2)+y y_(2) =a^(2), ` and `x x _(3)+y y_(3)=a^(2)`, respectively. These three lines will be concurrent , if
`|{:(x_(1),y_(1),-a^(2)),(x_(2),y_(2),-a^(2)),(x_(3),y_(3),-a^(2)):}|=0`
or `|{:(x_(1),y_(1),1),(x_(2),y_(2),1),(x_(3),y_(3),1):}|=0`
Therefore, points `(x_(1),y_(1)),(x_(2),y_(2))` and `(x_(3),y_(3))` are collinear.