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(1+sin2A-cos2A)/(1+sin2A+cos2A)=tanA...

`(1+sin2A-cos2A)/(1+sin2A+cos2A)=tanA`

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`(1+sin 2A-cos^(2)A)/(1+sin2A+cos2A)=((1-cos2A)+sin2A)/((1+cos2A)+sin2A)`
`=(2sin^(2)A+2sinAcosA)/(2cos^(2)A+2sinA cos A)`
`=(2sin A(sinA+cosA))/(2cosA(sinA+cosA))=tanA`
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