If `sin alpha=A sin(alpha+beta),Ane0`, then
The value of `tan alpha` is

Options

A. `(sinalpha(1+A cos beta))/(A cos alpha cos beta)`
B. `(sinalpha(1-A cos beta))/(A cos alpha cos beta)`
C. `(cos (1-A sinbeta))/(A cos alpha cos beta)`
D. `(cos alpha(1+A sin beta))/(A cos alpha cos beta)`

Answer

B

Explanation

`tan beta = (sin beta)/(cosbeta) = ((1-Acosbeta) tan alpha )/(A cos beta)`
`" " = ((1-A cos beta) sin alpha )/(A cos alpha cos beta)" " ` [from Eqs. (i) and (ii)]