Solve the following equation: `\ 3cos^2theta-2\ sqrt(3)sinthetacostheta-3sin^2theta=0`

Answer

`theta=(n pi)/2+pi/6, n in Z`

Explanation

`3(cos^(2) theta-sin^(2) theta)=2sqrt(3) sin theta cos theta`
or `3 cos 2 theta=sqrt(3) sin 2 theta`
or `tan 2 theta=sqrt(3) = tan (pi//3)`
`rArr 2 theta=n pi + pi//3`
or `theta =npi//2+pi//6, n in Z`