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Solve 2 sin^(3) x=cos x....

Solve `2 sin^(3) x=cos x`.

Text Solution

Verified by Experts

The correct Answer is:
`x= npi +pi/4, n in Z`
Since `sin x=0` does not satisfy the equation, dividing the equation by `sin^(3)x` we get
`cot x osec^(2) x=2`
or `cot^(3)x+cot x-2=0`
or `(cot x-1) (cot^(2) x+cot x+2)=0`
or `cot x=1`
`rArr x=npi+pi//4, n in Z`
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