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Solve sin 2x+cos 4x=2....

Solve `sin 2x+cos 4x=2`.

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The correct Answer is:
No solution
`sin 2x+cos 4x=2`
It is possible only when `sin 2x=1` and `cos 4x=1`
`2x=2npi+pi/2 and 4x=2mpi`
`:. X= npi +pi/4 and x= (mpi)/2`, where `m, n in Z`
Then, solution is given by
`(n pi +pi/4, n in I) nn ((mpi)/2, m in Z)= phi`
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