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The general solution of the equation, 2c...

The general solution of the equation, `2cot.(theta)/(2)=(1+cot theta)^(2)` is `(n in Z)`

A

`n pi+(-1)^(n)(pi)/(4)`

B

`n pi+(-1)^(n)(pi)/(6)`

C

`n pi+(-1)^(n)(pi)/(3)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`2cot.(theta)/(2)=(1+cot thetas)^(2)`
`rArr (2.2 cos theta//2.cos theta//2)/(2 sin theta//2.cos theta//2)=(1+cos theta)^(2)`
`rArr (2(1+cos theta))/(sin theta)=cosec^(2)theta + 2 cos theta`
`rArr sin theta =1//2`
`rArr theta = n pi +(-1)^(n)(pi)/(6), n in Z`
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