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Let veca,vecb,vecc be three unit vectors...

Let `veca,vecb,vecc` be three unit vectors such that `3veca+4vecb+5vecc=vec0`. Then which of the following statements is true? (A) `veca` is parrallel to vecb` (B) `veca` is perpendicular to vecb` (C) `veca` is neither parralel nor perpendicular to `vecb` (D) `veca,vecb,vecc` are copalanar

A

`veca` is parallel to `vecb`

B

`veca` is perpendicular to `vecb`

C

`veca` is neither parallel nor perpendicular to `vecb`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D
`3veca + 4vecb + 5vecc =0`
Hence `veca, vecb and vecc` are collinear.
No other conclusion can be derived from it.
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