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Let veca,vecb,vecc be three linearly ind...

Let `veca,vecb,vecc` be three linearly independent vectors, then `([veca+2vecb-vecc 2veca+vecb+vecc4veca-vecb+5vecc])/([vecavecbvecc])`

A

0

B

1

C

2

D

`-1`

Text Solution

Verified by Experts

The correct Answer is:
A
`vecx=veca+2vecb-vecc`
`vecy=2veca+vecb+vecc`
`vecz=4veca-vecb+5vecc`
Now `|{:(1,2,-1),(2,1,1),(4,-1,5):}|=0`
Thus, vectors are coplanar.
`rArr [veca +2vecb-vecc, 2veca+vecb+vecc , 4veca-vecb+5vecc]=0`
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