If the line (x-2)/-1=(y+2)/1=(z+k)/4 is ...

If the line `(x-2)/-1=(y+2)/1=(z+k)/4` is one of the angle bisector of the lines `x/1=y/-2=z/3` and `x/-2=y/3=z/1` then the value of k is

A

1

B

2

C

4

D

8

Verified by Experts

The correct Answer is:

D

Since point of intersecting of the given lines is (0,0,0), it must lie on the angle bisector.
So, `(0-2)/-1=(0+2)/1=(0+k)/4`
`rArr k=8`

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