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The distance of the point (1,-2,3) from ...

The distance of the point `(1,-2,3)` from the plane `x-y+z-5=0`, measured parallel to the line `x/2=y/3=(z-1)/-6` is equal to

A

1 unit

B

2 unit

C

3 units

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A

Equation of line parallel to given line and through `(1,-2,3)` is `(x-1)/2=(y+2)/3=(z-3)/-6` …………(1)
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CENGAGE-EQUATION OF PLANE AND ITS APPLICATIONS -I -DPP 3.3
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  2. Show that the disease of the point of intersection of the line (x-2)/3...

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  3. The value of k for which the planes kx+4y+z=0, 4x+ky+2z=0 nd 2x+2y+z=0...

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  4. Let P=-(1,7,sqrt(2)) be a point and line L is 2sqrt(2)(x-1)=y-2,z=0. I...

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  5. Angle between the two planes of which one plane is 4x +y + 2z=0 and a...

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  6. The distance of the point (1,-2,3) from the plane x-y+z-5=0, measured ...

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  7. The angle between the pair of planes represented by equation 2x^2-2y^2...

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  8. The Cartesian equation of the plane vec r=(1+lambda-mu) hat i+(2-l...

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  9. The locus represented by xy+yz=0 is a pair of

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  13. In X-Y plane, the path defined by the equation (1)/(x^(m))+(1)/(y^(m))...

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  14. Consider the equation E(1):vecr xx (2hati-hatj+3hatk)=3hati+hatk an...

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  15. the equationof a plane is 2x-y-3z=5 and A(1,1,1),B(2,1,-3),C(1,-2,-2) ...

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  16. Let P denotes the plane consisting of all points that are equidistant ...

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  17. Let P denotes the plane consisting of all points that are equidistant ...

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