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If a(p+q)^2+2b p q+c=0abd a(p+r)^2+2b p ...

If `a(p+q)^2+2b p q+c=0abd a(p+r)^2+2b p r+c=0(a!=0)` , then a.`q r=p^2` b. `q r=p^2+c/a` c. `q r=p^2` d. none of these

A

`qr = p^(2)`

B

`qr = p^(2) + c/a`

C

`qr = -p^(2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
2
Given, `a(p + q)^(2) + 2bpq + c = 0 and a(p + r)^(2) + 2bpr + c = 0`
`rArr` q and r satisfy the equation `a(p + x)^(2) + 2bpx + c = 0`
`rArr` q and r are the roots of `ax^(2) + 2(ap + bp)x + c + ap^(2) = 0`
`rArr` qr = Product of roots `= (c + ap^(2))/(a) = p^(2) + c/a`
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