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For the quadratic equation x^2+2(a+1)x+9...

For the quadratic equation `x^2+2(a+1)x+9a-5=0,` which of the following is/are true? (a) If 2 < a< 5 then roots are opposite sign `
` (b)If `a<0` , then roots are opposite in sign (c) if `a>7` then both roots are negative (d) if `2<=a<=5` then roots are unreal

A

If ` 2 lt a lt 5` , then roots are of opposite sign .

B

If ` a lt 0, ` then roots are of opposite sign

C

If ` a gt 7` , then both roots are negative .

D

If `2 le a le 5` , then roots are unreal.

Text Solution

Verified by Experts

The correct Answer is:
2,3,4

Given equation is
`x^(2) + 2 (a + 1) x + 9 a - 5 = 0 `
` D = 4 (a + 1)^(2) - 4 (9a - 5) = 4 (a -1) (a - b)`
` D ge 0 rArr a le 1 or a ge 6`
If ` a lt 0 `, then ` 9a - 5 lt 0 ` . Hence, the products of roots is less
then 0.So, the roots are of opposite sign .If ` a gt 7`, then sum of
roots is ` - 2(a + 1) lt 0 ` . Product of roots is greater then 0
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