If `(b+c-a)/a ,(c+a-b)/b ,(a+b-c)/c ,` are in A.P., prove that `1/a ,1/b ,1/c` are also in A.P.

Explanation

`(b+c-a)/a,(c+a-b)/b,(a+b-c)/c` are in A.P
`rArr{(b+c-a)/a+2},{(c+a-b)/b+2},{(a+b-c)/c+2}`
are in A.P [Adding 2 to each other]
`rArr(a+b+c)/a,(a+b+c)/b,(a+b+c)/c` are in A.P
`rArr 1/a',1/b,1/c` are in A.P. [ Dividing each term by a+b+c]