The third term of a geometric progression is 4. Then find the product of the first five terms.

Explanation

Let a be the first term and r be the common ratio of G.P.
Given that the third term is 4.
`thereforear^(2)=4`
`therefore` Product of first five terms=`axxarxxar^(2)xxar^(3)xxar^(4)`
`=a^(5)r^(10)=(ar^(2))^(5)=4^(5)`