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If nine arithmetic means and nine harmonic means are inserted between 2 and 3 alternatively, then prove that `A+6//H=5` (where `A` is any of the A.M.'s and `H` the corresponding H.M.)`dot`

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Let `H_(1),H_(2),..H_(9)` be nine harmonic means are inserted between 2 and 3 alternatively, then prove that A+6/H=5 (where A is any of the A.M.'s and H the corresponding H.M.).
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