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If `t_n` denotes the nth term of the series 2+3+6+11+18+….. Then `t_50` is

A

`49^2-1`

B

`49^2`

C

`50^2+1`

D

`49^2+2`

Text Solution

Verified by Experts

The correct Answer is:
D

`2+3+6+11+18+…`
`=(0^(2)+2)+(1^(2)+2)+(2^(2)+2)+(3^(2)+2)+…`
Hence, `t_(50)=49^(2)+2`.
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CENGAGE-PROGRESSION AND SERIES-Exercise (Single)
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  9. The sum to 50 terms of the series 3/1^2+5/(1^2+2^2)+7/(1^+2^2+3^2)+...

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  14. The greatest interger by which 1+Sigma(r=1)^(30) rxxr ! is divisible...

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