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The numbers 1, 4, 16 can be three terms ...

The numbers 1, 4, 16 can be three terms (not necessarily consecutive) of a.no. A.P b.only one G.P c.infinite number of A.P's d.infinite nuber of G.P' s

A

no. A.P

B

only one G.P

C

infinite number of A.P's

D

infinite nuber of G.P' s

Text Solution

Verified by Experts

The correct Answer is:
C, D

`4=1+(n-1)d,16=1+(m-1)d`
`rArr15/3=(m-1)/(n-1)` or
`(n-1)/1=(m-1)/5`=p= positive integer.
`thereforen=p+1,m=5p+1`. So, n,m have infinite pairs of values.
also, 4=1`cdotr^(n),16=1cdotr^(m)`
`rArrr^(2n)=r^(m)rArr2n=m`
`thereforem/2=n/1=q`= Positive integer.
So,m,m have infinite pairs of values.
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  18. If 1/(b-a)+1/(b-c)=1/a+1/c , then a ,b ,a n dc are in H.P. a ,b ,a n d...

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  19. If a,b,c are three distinct numbers in G.P., b,c,a are in A.P and a,bc...

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