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1/(sqrt(2)+sqrt(5))+1/(sqrt(5)+sqrt(8))+...

`1/(sqrt(2)+sqrt(5))+1/(sqrt(5)+sqrt(8))+1/(sqrt(8)+sqrt(11))+ n` terms is equal to a. `((sqrt(3n +2))-sqrt(2))/(3) b.(n)/(sqrt(2+3n)+sqrt(2)) `c.less than n d.less than `sqrt(n/3)`

A

`((sqrt(3n +2))-sqrt(2))/(3)`

B

`(n)/(sqrt(2+3n)+sqrt(2))`

C

less than n

D

less than `sqrt(n/3)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`1/(sqrt2+sqrt5)+1/(sqrt5+sqrt8)+1/(sqrt8+sqrt(11))+…` n terms
`=(sqrt5-sqrt2)/3+(sqrt8-sqrt5)/3+….+(sqrt(5+(n-1)3)-sqrt(2+(n-1)3))/3`
`=(sqrt(3n+2)-sqrt2)/3`
`=(3n+2-2)/(3(sqrt(3n+2)+sqrt2))`
`=n/(sqrt(3n+2)+sqrt2)`
`=n/(sqrt(2+3n)+sqrt2)ltn/(sqrt(3n))ltn`
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