It is given that in a group of `4` students, the probability of `2` students not having the same birthday is `0.893`. What is the probability that the `2` students have the same birthday?
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`d rarr q,t`
`(2ab)/(a+b)=4` `rArrab=2a+2b` Now, q=10 -a and 2q=5+b `rArr20-2a=5+b` `rArr15=2a+b` (2) From (1) and (2), a(15-2a)=2a+2(15-2a) `rArr15a-2a^(2)=-2a+30` `rArr2a^(2)-17a+30=0` `rArr a=6,5/2` accordingly q=4, `15/2` `rArrabs(q-a)=2,5` Note: Solutions pff the remaining parts are given in their respective chapters.
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