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Find the number of seen letter words tha...

Find the number of seen letter words that can be formed by using the letters of the word SUCCESS so that the two C are together but no two S are together.

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We have letters (S,S,S),U,(C,C),E.
Let us first arrange (C,E),U and E.
Considering C C as single object, U, C,C,E can be arranged in 3! Ways.
`xxUxx(C C)xxExx`.
Here four gaps are created, marked with `xx`.
Since no tow S are together, three S's can be put in places marked with `xx`.
Three places can be selected in `.^(4)C_(3)` ways, in which S's can be arranged in one way.
So, total number of arrangements `=3!xx .^(4)C_(3)=24`.
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