Home
Class 12
MATHS
If a curve y=f(x) passes through the poi...

If a curve `y=f(x)` passes through the point `(1,-1)` and satisfies the differential equation `,y(1+x y)dx""=x""dy` , then `f(-1/2)` is equal to: (1) `-2/5` (2) `-4/5` (3) `2/5` (4) `4/5`

A

`-4/5`

B

`2/5`

C

`4/5`

D

`-2/5`

Text Solution

Verified by Experts

The correct Answer is:
C

`y(1+xy)dx=xdy`
`rArr ydx-xdy+xy^(2)dx=0`
`rArr y^(2)d(x/y)+xy^(2)dx=0`
`rArr x/y+x^(2)/2=C`………….(1)
Curve passes through `(1,-1)`
`rArr -1+1/2=C` (form 1)
`rArr C=-1/2`
`rArr C=-1/2`
`rArr x/y+x^(2)/2=-1/2`
Now put `x=-1/2`
`rArr (-1/2)/(y)+(1/4)1/(2)=-1/2`
`rArr -1/(2y)=-1/2-1/8`
`y=4/5`
Promotional Banner

Topper's Solved these Questions

  • DIFFERENTIAL EQUATIONS

    CENGAGE|Exercise JEE Advanced Previous Year|12 Videos
  • DIFFERENTIAL EQUATIONS

    CENGAGE|Exercise Single Correct Answer Type|37 Videos
  • DIFFERENTIAL EQUATIONS

    CENGAGE|Exercise Exercise (Numerical)|15 Videos
  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE|Exercise Exercise|337 Videos
  • DIFFERENTIATION

    CENGAGE|Exercise Numerical Value Type|3 Videos

Similar Questions

Explore conceptually related problems

The graph of the function y = f(x) passing through the point (0, 1) and satisfying the differential equation (dy)/(dx) + y cos x = cos x is such that

Let y=f(x) be a function satisfying the differential equation (x d y)/(d x)+2 y=4 x^2 and f(1)=1 . Then f(-3) is equal to

If y = y(x) is the solution of the differential equation, x dy/dx+2y=x^2 satisfying y(1) = 1, then y(1/2) is equal to

A function y=f(x) satisfies the differential equation (d y)/(d x)+x^2 y=-2 x, f(1)=1 . The value of |f^( prime prime)(1)| is

Let y = y(x) be the solution of the differential equation x dy/dx+y=xlog_ex,(xgt1)." If " 2y(2)=log_e4-1," then "y(e) is equal to

If f(x) is differentiable and int_0^(t^2)xf(x)dx=2/5t^5, then f(4/(25)) equals (a) 2/5 (b) -5/2 (c) 1 (d) 5/2

The curve passing through the point (1,1) satisfies the differential equation (dy)/(dx)+(sqrt((x^2-1)(y^2-1)))/(x y)=0 . If the curve passes through the point (sqrt(2),k), then the value of [k] is (where [.] represents greatest integer function)_____

The solution of differential equation (y(2x^4+y)dy)/(dx)=(1-4x y^2)x^2 is given by

The slope of the tangent to a curve y=f(x) at (x,f(x)) is 2x+1. If the curve passes through the point (1,2) then the area of the region bounded by the curve, the x-axis and the line x=1 is (A) 5/6 (B) 6/5 (C) 1/6 (D) 1

Solution of the differential equation {1/x-(y^2)/((x-y)^2)}dx+{(x^2)/((x-y)^2)-1/y}dy=0 is