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The equation of the normal to the curve ...

The equation of the normal to the curve parametrically represented by `x=t^(2)+3t-8 and y=2t^(2)-2t-5` at the point `P(2,-1)` is

A

`2x+3y-1=0`

B

`6x-7y-11=0`

C

`7x+6y-8=0`

D

`3x+y-1=0`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(t^(2)+3t-8=2 rArrt=2","-5),(2t^(2)-2t-5=-1 rArr t=2","-1):}}`
`rArr" "t=2,(dy)/(dx)=(4t-2)/(2t+3)rArr ((dy)/(dx))_(t=2)=(6)/(7)`
`therefore" Equation of normal y + 1"=(-7)/(6)(x-2)`
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