The tangent at any point on the curve `x = at^3. y = at^4` divides the abscissa of the point of contact in the ratio m:n, then `|n + m|` is equal to (m and n are co-prime)
A
`1//4`
B
`3//4`
C
`3//2`
D
`2//5`
Text Solution
Verified by Experts
The correct Answer is:
B
`(dy)/(dx)=(4t)/(3)` Tangent is `y-at^(4)=(4t)/(3)(x-at^(3))` x-intercept`=(at^(3))/(4)` y-intercept `=(at^(4))/(3)` the point of intersection of tangent with the axes are `((at^(3))/(4),0) and (0,-(at^(4))/(3))` `therefore" "(m)/(n)=-(3)/(4)`
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