Given `f'(1)=1and f(2x)=f(x)AAxgt0.If f'(x)` is differentiable, then there exists a number `c in (2,4)` such that `f''(c )` equal
A
`1//4`
B
`-1//2`
C
`-1//4`
D
`-1//8`
Text Solution
Verified by Experts
The correct Answer is:
D
Given `f'(1)=1,` And `f(2x)=f(x)` `rArr" "2f'(2x)=f'(x)` Putting x = 1, `f'(2)=(f'(1))/(2)=(1)/(2)` Putting x = 2, `f'(4)=(f'(2))/(2)=(1)/(4)` Now applying LMVT for `y=f'(x)` in `[2, 4]` We get `f''(c)=(f'(4)-f'(2))/(2)=((1)/(4)-(1)/(2))/(2)=-(1)/(8)`
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