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For y gt 0 and x in R, ydx + y^(2)dy = x...

For `y gt 0 and x in R, ydx + y^(2)dy = xdy` where y = f(x). If f(1)=1, then the value of f(-3) is

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
C
`(x dy-y dx)/(y^(2))=dy`
`rArr" "-int d((x)/(y))=int dy`
`rArr" "-(x)/(y)=y+c`
At `x = 1, y = 1" "therefore" "c = -2`
At `x = -3, (3)/(y)=y-2`
`rArr" "y^(2)-2y - 3 = 0`
`rArr" "y = 3`
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