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Find the length of normal to the curve x...

Find the length of normal to the curve `x=a(theta+sintheta),y=a(1-costheta)` at `theta=pi/2dot`

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Find the slope of the normal to the curve x=1 -a sin theta , y = b cos^(2) theta at theta= (pi)/(2) .

Find the slope of the normal to the curve x=a cos^(3) theta,y=a sin^(3) theta at theta=(pi)/(4) .

If x=a(theta+sintheta), y=a(1-costheta) then prove that at theta=pi/2, y''=1/a .

If x=a(theta+sintheta), y=a(1+costheta) " then " (dy)/(dx) is

(sintheta+sin2theta)/(1+costheta+cos2theta)

Show that the equation of the normal to the curve x=a cos ^(3) theta, y=a sin ^(3) theta at 'theta ' is x cos theta -y sin theta =a cos 2 theta .

Prove that sin^2theta

Prove that (sintheta +sin2theta)/(1+costheta +cos2theta)=tantheta

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