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Then angle of intersection of the normal...

Then angle of intersection of the normal at the point `(-5/(sqrt(2)),3/(sqrt(2)))` of the curves `x^2-y^2=8` and `9x^2+25 y^2=225` is 0 (b) `pi/2` (c) `pi/3` (d) `pi/4`

A

0

B

`(pi)/(2)`

C

`(pi)/(3)`

D

`(pi)/(4)`

Text Solution

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The correct Answer is:
B
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CENGAGE-APPLICATION OF DERIVATIVES-Exercise (Single)
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