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If f(x)=(x^2-bx+25)/(x^2-7x+10) for x!=5...

If `f(x)=(x^2-bx+25)/(x^2-7x+10)` for `x!=5` and `f` is continuous at `x=5` then `f(5)=`

A

0

B

5

C

10

D

25

Text Solution

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The correct Answer is:
A
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